Problem : https://leetcode.com/problems/binary-tree-upside-down/
Although it says every node has either 0 or 2 children in the given example. The input tree may only has left sub-tree.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def upsideDownBinaryTree(self, root: TreeNode) -> TreeNode:
def helper(node):
if node and node.left:
lt = node.left
node.left = None
lt = helper(lt)
rt = node.right
node.right = None
rt = helper(rt)
np = lt
while np.right:
np = np.right
np.left = rt
np.right = node
return lt
else:
return node
return helper(root)
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