Swap nodes in pairs recursively.
Time Complexity : O ( N ) , N = length of list
Space Complexity: O ( 1 ), swap in space.
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution(object):
def swapPairs(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if head and head.next:
tmp = head.next.next
left, right = head, head.next
right.next = left
left.next = self.swapPairs(tmp)
return right
return head
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